5x^2+145=-60x

Solution for 5x^2+145=-60x equation:

5x^2+145=-60x

We move all terms to the left:

5x^2+145-(-60x)=0

We get rid of parentheses

5x^2+60x+145=0

a = 5; b = 60; c = +145;
Δ = b2-4ac
Δ = 602-4·5·145
Δ = 700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{700}=\sqrt{100*7}=\sqrt{100}*\sqrt{7}=10\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-10\sqrt{7}}{2*5}=\frac{-60-10\sqrt{7}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+10\sqrt{7}}{2*5}=\frac{-60+10\sqrt{7}}{10}
$